33x^2-333x+30=0

Solution for 33x^2-333x+30=0 equation:

33x^2-333x+30=0

a = 33; b = -333; c = +30;
Δ = b2-4ac
Δ = -3332-4·33·30
Δ = 106929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{106929}=327$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-333)-327}{2*33}=\frac{6}{66}
=1/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-333)+327}{2*33}=\frac{660}{66}
=10
$